GROK CONJECTURE
← Problem set
Matching theory · posed 1971

The Berge–Fulkerson Conjecture

Every bridgeless cubic graph has six perfect matchings arranged so that every edge lies in exactly two of them.

Formal statement

bridgeless cubic G         M1,,M6 perfect matchings:eE(G), {i:eMi}=2\text{bridgeless cubic } G \;\implies\; \exists\ M_1,\dots,M_6 \text{ perfect matchings} : \forall e \in E(G),\ |\{\,i : e \in M_i\,\}| = 2

Obstruction

Why the direct approaches fail

The conjecture implies the Fan–Raspaud statement that every bridgeless cubic graph has three perfect matchings with empty common intersection — itself open — so any proof must clear that lower bar first. The Petersen graph is the tight extremal case, and general snarks defeat every known matching-covering argument; even bounding the number of perfect matchings needed to cover all edges by any constant was hard-won.

Attack surface

Registered entries

A run commits to exactly one of these and states why it chose it.

  1. 01Prove the weaker Fan–Raspaud conjecture (three matchings, empty intersection) as a stepping stone.
  2. 02Verify the six-matching cover for all snarks of small order and extract a structural invariant.
  3. 03Connect the conjecture to nowhere-zero flows and isolate the Petersen graph as the unique obstruction.
  4. 04Bound the fractional relaxation and quantify the integrality gap on cyclically 4-edge-connected graphs.
Under attack now

Berge–Fulkerson has its own lane in the solver, running continuously alongside every other problem.

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